Why is Curium the Last Semi-Stable Element?

Mathis wrote:Now, why would Graphene be inert when completely flat, but conduct well when deformities are introduced?

Simply because if you spread those three lower bonds out completely, matching them to the equator of the nucleus, you will have short-circuited the charge channeling of the atom. Charge channeling is normally either pole to equator, or pole to pole. But each profile has its own mechanics. Pole-to-pole channeling is through-charge, is linear, and it relies on field differentials top to bottom. It relies on a north/south pull, or a charge density differential top to bottom. Pole-to-equator channeling relies on the spin of the nucleus and its roughly spherical shape. During spin, the equator has more angular momentum, which draws charge out that way via a centrifugal effect. But here, we have a sort of mixed situation, where a polar charge stream is then spread out at 90 degrees angles. It comes in a pole, vertically, and then is released horizontally. That can't work because there is no logical mechanics for it. The charge density variations top to bottom don't apply, since—technically—there is no south pole any longer. Yes, we can still plug in neutrons down there, as I showed above, but for the three protons, the south pole no longer exists. They are releasing horizontally or equatorially, so there is no pull from a south pole. The pull to the side of the atom simply doesn't exist in the same way.

There aren't lower charge densities out there, so there is no “pull”. And, in the same way, there is no centrifugal effect to work with. Although there is no real south pole for these three protons, they are still plugged into the nuclear axis. They are getting their charge stream from the spin axis, so that charge stream can't feel any centrifugal effect. During spin, a sphere feels no centrifugal effect from the center or from any point on the spin axis.

Some will say, “Then why doesn't the nucleus dissolve in that case? If no charge is running through it, what is holding it together?” Three things.
One, we still have gravity, which the mainstream has mismeasured at the quantum level by 10²².  http://milesmathis.com/quantumg.html
Two, we still have charge surrounding the nucleus like a powerful atmosphere. It supplies an external pressure.
Three, I assume that although the main charge streams have been broken, other minor ones persist. For instance, if we break that main line of charge, the nucleus can still channel through those neutrons on the south pole.
So if we went to 90 degrees and applied a current in the right way (from the south pole), we could force some amount of anticharge through the Graphene. The Graphene won't be completely inert, it just won't like our original current plugged in from the side.